by pfhoeycfi » Sun Mar 25, 2018 5:39 pm
...a couple of basic HVAC equations to estimate what you need...
heating application so sensible heat only...
Start on the water side...
the formula you need on the water side is
Q (btuh) = GPM * 500 * (T1-T2)
T1 - T2 is the water temp drop across the rad coil.
Similarly, having calculated Q...for the air side...
Q (btuh) = 1.08 * CFM * (T1-T2)
T1 - T2 is the air temp drop across the rad coil.
Assume an efficiency loss... meaning the Q actually transferred to air will be something less that the heat in the water. Guessing 70 - 80%. Coils used in HVAC apps have tables with this data...you're just looking to get close.
You can make it more complicated by including actual density of air and water but for simple space heating its just not necessary. The formulas apply for the heat rejection coil as well.
peter
Doylestown, Pa
Peter Hoey
SEL Pvt, Comm Glider, CFIG, Pawnee & L19 Towpilot
Philadelphia Glider Council
Sonex B SNB0021, N561PH, Taildragger, Aerovee Turbo, MGL MX1, First flight Dec 18, 2022
Also built Sonerai IIL N86PH