I am going to use a Rotax 912 ULS engine in my single place Onex experimental. This engine weighs about 170 lbs and it will be replacing the VW conversion engine normally in the Onex which weighs 190lbs. So I am doing the math below to figure out how many inches I need to move the new engine forward to compensate for its lighter weight. Using the weight and balance diagram below, the number of inches that the cg of the engine is forward of the wing is 48.6”. So the moment is 190 x 48.6 = 9,234.
If the new engine is 170 lbs, to get the same moment I would need to have the arm be:
9234 = “X” x 170
“X” = 9234/170
“X”= 54.32
So I would need to move the engine forward about 6” (54.32” – 48.6”=5.72”)
Is it really that simple or am I missing something?