Aerovee secondary/electronic ignition current draw?

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Aerovee secondary/electronic ignition current draw?

Postby kevinh » Fri Jul 28, 2017 9:28 pm

Hi ya'll,

So I'm making my wiring/electrical-endurance spreadsheet. Do any of ya'll know what the typical current draw is for the electronic ignition? I don't need super exact, just ballpark.

Kevin
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Re: Aerovee secondary/electronic ignition current draw?

Postby jjbardell » Sat Jul 29, 2017 6:50 am

I believe it is 7amps.
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Re: Aerovee secondary/electronic ignition current draw?

Postby kevinh » Sat Jul 29, 2017 9:26 am

Thanks. Really? Did you measure that? I say this for two reasons, the original aerovee alternator was only 10A and the electronic ignition on the IO360 clone I had in my RV was only 1.2A.

Kevin
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Re: Aerovee secondary/electronic ignition current draw?

Postby GordonTurner » Sat Jul 29, 2017 11:03 am

Without having any actual specifics for this case, I think Kevin is correct, 7 amps has the sound of being way too high.
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Re: Aerovee secondary/electronic ignition current draw?

Postby marsolgp » Sat Jul 29, 2017 8:22 pm

Actually jjbardel is close to correct.... I measured mine several years back and it was close to 7 amps!..... This was done cuz I was having trouble with battery charging and I believed the alternator was not putting out enough to operate all the equipment and charge the battery. As a side note, I have gotten into the habit of switching OFF the secondary ignition once I'm airborne. It makes a huge difference (for me) with voltage I see on my meter and in keeping the battery charged up. I switch it back ON once I'm back in the pattern.
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Re: Aerovee secondary/electronic ignition current draw?

Postby kevinh » Sat Jul 29, 2017 10:07 pm

Thanks! That helps a lot!
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Re: Aerovee secondary/electronic ignition current draw?

Postby wlarson861 » Sun Jul 30, 2017 12:00 am

Thanks. Really? Did you measure that? I say this for two reasons, the original aerovee alternator was only 10A and the electronic ignition on the IO360 clone I had in my RV was only 1.2A.

Kevin


I think the version 2.0 and later engines have a 20 amp alternator due to the addition of the electronic ignition. The versions with the 10 amp alt. were single ignition models.
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Re: Aerovee secondary/electronic ignition current draw?

Postby gammaxy » Sun Jul 30, 2017 9:30 am

The explanation for it being about 7 amps is that each coil is 4 ohms. The triggers charge each coil and reach a steady state current of about 13v/4ohm = 3.2 amps across each one. My first two coils failed around 200 hours after becoming 2 ohms and drawing double the current.

A different design could charge each coil just in time for when it is needed, but you have to provide enough margin for acceleration of the engine. The magnetron ignition works this way because it uses the passing magnet to charge the coil before triggering.

A capacitive discharge ignition would also draw much less average current. If the 7 amps quoted by others was measured with the engine running then the coils are constantly charged except briefly while firing. I haven't personally measured it but don't find it surprising.

I do know that the triggers turn off if they haven't fired in a while--this prevents draining the battery too much before starting the engine at the expense of not firing the first time the magnet passes when starting the engine.
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Re: Aerovee secondary/electronic ignition current draw?

Postby Bryan Cotton » Sun Jul 30, 2017 10:42 am

Interesting- sounds like we could use an inverter. Besides reducing the current we would dissapate less power in the coils and make less heat.
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Re: Aerovee secondary/electronic ignition current draw?

Postby SNX1508 » Mon Jul 31, 2017 4:07 am

gammaxy wrote:The explanation for it being about 7 amps is that each coil is 4 ohms. The triggers charge each coil and reach a steady state current of about 13v/4ohm = 3.2 amps across each one. My first two coils failed around 200 hours after becoming 2 ohms and drawing double the current.


Measuring the DC resistance of the coils and then calculating DC current does not result in the actual current when the engine is running, since the coils are an inductive load. In order to calculate the running state current the inductive reactance of the coils would have to be determined.

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